x^2+2(x+5)-36=0

Solution for x^2+2(x+5)-36=0 equation:

x^2+2(x+5)-36=0

We multiply parentheses

x^2+2x+10-36=0

We add all the numbers together, and all the variables

x^2+2x-26=0

a = 1; b = 2; c = -26;
Δ = b2-4ac
Δ = 22-4·1·(-26)
Δ = 108
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{108}=\sqrt{36*3}=\sqrt{36}*\sqrt{3}=6\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-6\sqrt{3}}{2*1}=\frac{-2-6\sqrt{3}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+6\sqrt{3}}{2*1}=\frac{-2+6\sqrt{3}}{2}
$